(1/8)^2n=64^-3n

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Solution for (1/8)^2n=64^-3n equation:



(1/8)^2n=64^-3n
We move all terms to the left:
(1/8)^2n-(64^-3n)=0
Domain of the equation: 8)^2n!=0
n!=0/1
n!=0
n∈R
We add all the numbers together, and all the variables
(+1/8)^2n-(64^-3n)=0
We get rid of parentheses
(+1/8)^2n+3n-64^=0
We multiply all the terms by the denominator
(+1+3n*8)^2n-64^*8)^2n=0
We add all the numbers together, and all the variables
(3n*8+1)^2n-64^*8)^2n=0
Wy multiply elements
-512n^2+(3n*8+1)^2n=0

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